Trang Ánh Nam has left a new comment on your post "Cho hình thang cân ABCD (AD//BC) đường cao BE cắt ...":
ở chổ "Lại có" các bạn có thể dùng Thales cũng được, nếu bạn nhớ.
còn đây là 1 cách giải khác:
Ta có: AF/FC =AE/BC =2/3
Do ABCD là h.t cân => AD = 2AE +BC
=> AD/BC = (2AE + BC)/BC = 2AE/BC + 1 = 4/3 + 1 =7/3
Mà AD/BC = AM/BM
=> AM/BM = 7/3
=> (AB+BM)/BM = AB/BM + 1 =7/3
=> AB/BM =4/3
=> BM = 3AB/4 = 15
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Posted by Trang Ánh Nam to Trang Ánh Nam at February 12, 2019 at 10:01 AM
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